Classical electrodynamics - Klassische Elektrodynamik by Wegner F.

By Wegner F.

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Example text

7) where ka is an external force density. 8) so that δU = − gelten muss. 9) holds. We bring now δU into this form ∂u ∂u · δD + ∂D ∂ρm δρm , u = u(D, ρm ). 10) D Wegen ∂u/∂D = E/(4π) formen wir den ersten Term wie im vorhergehenden Abschnitt um in δU = Since ∂u/∂D = E/(4π) we rewrite the first term as in the previous section ∂u d3 r Φ(r)δρf (r) + δρm . 11) ∂ρm D Aus der Kontinuit¨atsgleichung ∂ρ/∂t = − div j leiten wir nun den Zusammenhang zwischen δρ und δs her. Man muss die Gleichung nur mit δt multiplizieren und ber¨ucksichtigen, dass jδt = ρvδt = ρδs gilt.

10) 56 C Magnetostatik C Magnetostatics gilt. An der anderen Mgleichung div B(r) = 0 a¨ ndert sich dadurch nichts. holds. M’s equation div B(r) = 0 remains unchanged. 11) wobei χm als magnetische Suszeptibilit¨at und µ als relative Permeabilit¨at bezeichnet werden. Im Supraleiter erster Art ist B = 0 (vollst¨andiger Diamagnetismus). Die magnetische Induktion wird dort durch Oberfl¨achenstr¨ome vollst¨andig aus dem Material verdr¨angt. where χm is the magnetic susceptibility and µ the permeability.

53 This applies for orbital currents. 18) 2mc where s is the angular momentum of the spin. 0023 and the components of the spin s are ± /2. 927 · 10−20 dyn1/2 cm2 . α Force and Torque on a Dipole in an External Magnetic Field Force Eine a¨ ußere magnetische Induktion Ba u¨ bt auf einen An external magnetic induction Ba exerts on a loop of Ringstrom die L-Kraft a current the L force 1 1 ∂Ba ∂Ba 1 d3 rj(r) × Ba (r) = − Ba (0) × d3 rj(r) − × d3 rxα jβ (r)eβ − ... 19) K= c c c ∂xα ∂xα aus.

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